Engineering Mechanics

61. The C.G. of a plane lamina will not be at its geometrical centre in the case of a

  1. right angled triangle
  2. equilateral triangle
  3. square
  4. circle
  5. rectangle.

Correct answer: (A)
right angled triangle

62. The C.G. of a right circular solid cone of height h lies at the following distance from the base

  1. h/2
  2. J/3
  3. h/6
  4. h/4
  5. 3/i/5.

Correct answer: (D)
h/4

63. The C.G. of a solid hemisphere lies on the central radius 3r

  1. at distance — from the plane base 3r
  2. at distance — from the plane base 3r
  3. at distance — from the plane base 3r
  4. at distance — from the plane base or
  5. at distance — from the plane base.

Correct answer: (D)
at distance — from the plane base or

64. The center of gravity of a triangle lies at the point of

  1. concurrence of the medians
  2. intersection of its altitudes
  3. intersection of bisector of angles
  4. intersection of diagonals
  5. all of the above.

Correct answer: (A)
concurrence of the medians

65. The center of gravity of a uniform lamina lies at

  1. the center of heavy portion
  2. the bottom surface
  3. the mid point of its axis
  4. all of the above
  5. none of the above.

Correct answer: (C)
the mid point of its axis

66. The center of percussion of a solid cylinder of radius r resting on a horizontal plane will be

  1. r/2
  2. 2r/3
  3. r/A
  4. 3r/2
  5. 3r/A.

Correct answer: (D)
3r/2

67. The center of percussion of the homogeneous rod of length L suspended at the top will be

  1. L/2
  2. L/3
  3. 3L/4
  4. 2L/3
  5. 3L/8.

Correct answer: (D)
2L/3

68. The coefficient of friction depends on

  1. area of contact
  2. shape of surfaces
  3. strength of surfaces
  4. nature of surface
  5. all of the above.

Correct answer: (D)
nature of surface

69. The co-efficient of friction depends upon

  1. nature of surfaces
  2. area of contact
  3. shape of the surfaces
  4. ail of the above.
  5. (a) and (b) above.

Correct answer: (A)
nature of surfaces

70. The effort required to lift a load W on a screw jack with helix angle a and angle of friction <j) is equal to

  1. Wtan(a + <)>)
  2. Wtan(a-<)>)
  3. Wcos(a + <t>)
  4. Wsin(a + <(>)
  5. W (sin a + cos <j>).

Correct answer: (A)
Wtan(a + <)>)

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